**Abstract.** By a 35-year-old theorem of Shelah, $\square_\lambda+\diamondsuit(\lambda^+)$ does not imply square-with-built-in-diamond_lambda for regular uncountable cardinals $\lambda$.

Here, it is proved that $\square_\lambda+\diamondsuit(\lambda^+)$ is equivalent to square-with-built-in-diamond_lambda for every singular cardinal $\lambda$.

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**Citation information:**

A. Rinot, *Putting a diamond inside the square,* Bull. Lond. Math. Soc., 47(3): 436-442, 2015.

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